7y-2=3(1[y+6]1)

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Solution for 7y-2=3(1[y+6]1) equation:


Simplifying
7y + -2 = 3(1[y + 6] * 1)

Reorder the terms:
-2 + 7y = 3(1[y + 6] * 1)

Reorder the terms:
-2 + 7y = 3(1[6 + y] * 1)

Reorder the terms for easier multiplication:
-2 + 7y = 3(1 * 1[6 + y])

Multiply 1 * 1
-2 + 7y = 3(1[6 + y])
-2 + 7y = 3([6 * 1 + y * 1])
-2 + 7y = 3([6 + 1y])
-2 + 7y = (6 * 3 + 1y * 3)
-2 + 7y = (18 + 3y)

Solving
-2 + 7y = 18 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-2 + 7y + -3y = 18 + 3y + -3y

Combine like terms: 7y + -3y = 4y
-2 + 4y = 18 + 3y + -3y

Combine like terms: 3y + -3y = 0
-2 + 4y = 18 + 0
-2 + 4y = 18

Add '2' to each side of the equation.
-2 + 2 + 4y = 18 + 2

Combine like terms: -2 + 2 = 0
0 + 4y = 18 + 2
4y = 18 + 2

Combine like terms: 18 + 2 = 20
4y = 20

Divide each side by '4'.
y = 5

Simplifying
y = 5

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